Optimal. Leaf size=167 \[ \frac{\left (a^2-b^2\right )^2 \sin ^{n+1}(c+d x) \, _2F_1\left (1,n+1;n+2;-\frac{b \sin (c+d x)}{a}\right )}{a b^4 d (n+1)}-\frac{a \left (a^2-2 b^2\right ) \sin ^{n+1}(c+d x)}{b^4 d (n+1)}+\frac{\left (a^2-2 b^2\right ) \sin ^{n+2}(c+d x)}{b^3 d (n+2)}-\frac{a \sin ^{n+3}(c+d x)}{b^2 d (n+3)}+\frac{\sin ^{n+4}(c+d x)}{b d (n+4)} \]
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Rubi [A] time = 0.338371, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.138, Rules used = {2837, 952, 1620, 64} \[ \frac{\left (a^2-b^2\right )^2 \sin ^{n+1}(c+d x) \, _2F_1\left (1,n+1;n+2;-\frac{b \sin (c+d x)}{a}\right )}{a b^4 d (n+1)}-\frac{a \left (a^2-2 b^2\right ) \sin ^{n+1}(c+d x)}{b^4 d (n+1)}+\frac{\left (a^2-2 b^2\right ) \sin ^{n+2}(c+d x)}{b^3 d (n+2)}-\frac{a \sin ^{n+3}(c+d x)}{b^2 d (n+3)}+\frac{\sin ^{n+4}(c+d x)}{b d (n+4)} \]
Antiderivative was successfully verified.
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Rule 2837
Rule 952
Rule 1620
Rule 64
Rubi steps
\begin{align*} \int \frac{\cos ^5(c+d x) \sin ^n(c+d x)}{a+b \sin (c+d x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (\frac{x}{b}\right )^n \left (b^2-x^2\right )^2}{a+x} \, dx,x,b \sin (c+d x)\right )}{b^5 d}\\ &=\frac{\sin ^{4+n}(c+d x)}{b d (4+n)}+\frac{\operatorname{Subst}\left (\int \frac{\left (\frac{x}{b}\right )^n \left (4+n-\frac{2 (4+n) x^2}{b^2}-\frac{a (4+n) x^3}{b^4}\right )}{a+x} \, dx,x,b \sin (c+d x)\right )}{b d (4+n)}\\ &=\frac{\sin ^{4+n}(c+d x)}{b d (4+n)}+\frac{\operatorname{Subst}\left (\int \left (-\frac{a \left (a^2-2 b^2\right ) (4+n) \left (\frac{x}{b}\right )^n}{b^4}-\frac{\left (-a^2+2 b^2\right ) (4+n) \left (\frac{x}{b}\right )^{1+n}}{b^3}-\frac{a (4+n) \left (\frac{x}{b}\right )^{2+n}}{b^2}+\frac{\left (-a^2+b^2\right )^2 (4+n) \left (\frac{x}{b}\right )^n}{b^4 (a+x)}\right ) \, dx,x,b \sin (c+d x)\right )}{b d (4+n)}\\ &=-\frac{a \left (a^2-2 b^2\right ) \sin ^{1+n}(c+d x)}{b^4 d (1+n)}+\frac{\left (a^2-2 b^2\right ) \sin ^{2+n}(c+d x)}{b^3 d (2+n)}-\frac{a \sin ^{3+n}(c+d x)}{b^2 d (3+n)}+\frac{\sin ^{4+n}(c+d x)}{b d (4+n)}+\frac{\left (a^2-b^2\right )^2 \operatorname{Subst}\left (\int \frac{\left (\frac{x}{b}\right )^n}{a+x} \, dx,x,b \sin (c+d x)\right )}{b^5 d}\\ &=-\frac{a \left (a^2-2 b^2\right ) \sin ^{1+n}(c+d x)}{b^4 d (1+n)}+\frac{\left (a^2-b^2\right )^2 \, _2F_1\left (1,1+n;2+n;-\frac{b \sin (c+d x)}{a}\right ) \sin ^{1+n}(c+d x)}{a b^4 d (1+n)}+\frac{\left (a^2-2 b^2\right ) \sin ^{2+n}(c+d x)}{b^3 d (2+n)}-\frac{a \sin ^{3+n}(c+d x)}{b^2 d (3+n)}+\frac{\sin ^{4+n}(c+d x)}{b d (4+n)}\\ \end{align*}
Mathematica [A] time = 0.526008, size = 133, normalized size = 0.8 \[ \frac{\sin ^{n+1}(c+d x) \left (\frac{\left (a^2-b^2\right )^2 \, _2F_1\left (1,n+1;n+2;-\frac{b \sin (c+d x)}{a}\right )}{a (n+1)}+\frac{b \left (a^2-2 b^2\right ) \sin (c+d x)}{n+2}-\frac{a^3-2 a b^2}{n+1}-\frac{a b^2 \sin ^2(c+d x)}{n+3}+\frac{b^3 \sin ^3(c+d x)}{n+4}\right )}{b^4 d} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.802, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( \cos \left ( dx+c \right ) \right ) ^{5} \left ( \sin \left ( dx+c \right ) \right ) ^{n}}{a+b\sin \left ( dx+c \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin \left (d x + c\right )^{n} \cos \left (d x + c\right )^{5}}{b \sin \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sin \left (d x + c\right )^{n} \cos \left (d x + c\right )^{5}}{b \sin \left (d x + c\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin \left (d x + c\right )^{n} \cos \left (d x + c\right )^{5}}{b \sin \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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